w83627hf/acpi: Fix endianess error in floppy drive enumeration code
The enumeration results are stored as five DWORDs in one 20 byte buffer. Bytes 3, 7, 11 and 15 were used to set the lowest bit of each DWORD. ACPI uses little endian, so 1, 4, 8 and 12 are the correct indices. Change-Id: I793225cb1bb62fd148ecfa1e61e02f5d7be62cdb Signed-off-by: Christoph Grenz <christophg+cb@grenz-bonn.de> Reviewed-on: http://review.coreboot.org/3602 Tested-by: build bot (Jenkins) Reviewed-by: Ronald G. Minnich <rminnich@gmail.com>
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@ -356,10 +356,10 @@ Device(SIO) {
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SIFR, 8
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}
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CreateByteField (_FDE, 3, FD1)
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CreateByteField (_FDE, 7, FD2)
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CreateByteField (_FDE, 11, FD3)
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CreateByteField (_FDE, 15, FD4)
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CreateByteField (_FDE, 1, FD1)
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CreateByteField (_FDE, 4, FD2)
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CreateByteField (_FDE, 8, FD3)
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CreateByteField (_FDE, 12, FD4)
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Store(One, ACT1)
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Store(0, SELE)
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