uart: Fix bug in {uart8250, uart8250_mem, ns16550}_rx_byte functions
We have several different UART implementations of which three support a timeout when receiving characters. In all of these three implementations there is a bug where when the timeout is hit the last received character will be returned instead of the needed 0. The problem is that the timeout variable i is decremented after it has been checked in the while-loop. That leads to the fact that when the while-loop is aborted due to a timeout i will contain 0xffffffff and not 0. Thus in turn will fool the following if-statement leading to wrong return value to the caller in this case. Therefore the caller will see a received character event if there is none. Change-Id: I23ff531a1e729e816764f1a071484c924dcb0f85 Signed-off-by: Werner Zeh <werner.zeh@siemens.com> Reviewed-on: https://review.coreboot.org/19731 Tested-by: build bot (Jenkins) <no-reply@coreboot.org> Reviewed-by: Aaron Durbin <adurbin@chromium.org>
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@ -62,7 +62,8 @@ static int uart8250_can_rx_byte(unsigned base_port)
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static unsigned char uart8250_rx_byte(unsigned base_port)
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{
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unsigned long int i = SINGLE_CHAR_TIMEOUT;
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while (i-- && !uart8250_can_rx_byte(base_port));
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while (i && !uart8250_can_rx_byte(base_port))
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i--;
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if (i)
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return inb(base_port + UART8250_RBR);
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@ -82,8 +82,10 @@ static int uart8250_mem_can_rx_byte(void *base)
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static unsigned char uart8250_mem_rx_byte(void *base)
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{
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unsigned long int i = SINGLE_CHAR_TIMEOUT;
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while (i-- && !uart8250_mem_can_rx_byte(base))
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while (i && !uart8250_mem_can_rx_byte(base)) {
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udelay(1);
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i--;
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}
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if (i)
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return uart8250_read(base, UART8250_RBR);
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else
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@ -84,8 +84,10 @@ static int ns16550_tst_byte(void)
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static unsigned char ns16550_rx_byte(void)
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{
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unsigned long int i = SINGLE_CHAR_TIMEOUT;
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while (i-- && !ns16550_tst_byte())
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while (i && !ns16550_tst_byte()) {
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udelay(1);
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i--;
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}
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if (i)
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return read32(®s->rbr);
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else
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