soc/amd/stoneyridge/gpio.c: Fix gpio_output()

Function gpio_output() is only setting the pin as an output, when in fact
it should also set the state (high/low) of the pin. Fix the procedure to
set the state of the pin.

BUG=b:78328773
TEST=None

Change-Id: I516192a0782a9bbb40124029f264a2711114c800
Signed-off-by: Richard Spiegel <richard.spiegel@silverbackltd.com>
Reviewed-on: https://review.coreboot.org/25871
Tested-by: build bot (Jenkins) <no-reply@coreboot.org>
Reviewed-by: Martin Roth <martinroth@google.com>
Reviewed-by: Aaron Durbin <adurbin@chromium.org>
Reviewed-by: Paul Menzel <paulepanter@users.sourceforge.net>
This commit is contained in:
Richard Spiegel 2018-04-26 08:19:12 -07:00 committed by Patrick Georgi
parent ccfa18feff
commit 7a52c17f16
1 changed files with 1 additions and 0 deletions

View File

@ -95,6 +95,7 @@ void gpio_output(gpio_t gpio_num, int value)
reg = read32((void *)gpio_address); reg = read32((void *)gpio_address);
reg |= GPIO_OUTPUT_ENABLE; reg |= GPIO_OUTPUT_ENABLE;
write32((void *)(uintptr_t)gpio_num, reg); write32((void *)(uintptr_t)gpio_num, reg);
gpio_set(gpio_num, value);
} }
const char *gpio_acpi_path(gpio_t gpio) const char *gpio_acpi_path(gpio_t gpio)