rtc: Fix rtc_calc_weekday
This function appeared previously unused (called only from rtc_display, also unused), but it returned an incorrect weekday. Change the algorithm to use Zeller's Rule, a well-known algorithm for calculuating weekdays. Change-Id: Ibce6822942f8d9d9f39c2b6065cd785dca9e8e09 Signed-off-by: Tim Wawrzynczak <twawrzynczak@chromium.org> Reviewed-on: https://review.coreboot.org/c/31557 Tested-by: build bot (Jenkins) <no-reply@coreboot.org> Reviewed-by: Julius Werner <jwerner@chromium.org>
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@ -27,50 +27,34 @@
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#define DAYS_IN_YEAR(a) (LEAP_YEAR(a) ? 366 : 365)
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#define DAYS_IN_MONTH(a) (month_days[(a) - 1])
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static const int month_offset[] = {
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0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334
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};
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static const char *const weekdays[] = {
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"Sun", "Mon", "Tues", "Wednes", "Thurs", "Fri", "Satur",
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"Sun", "Mon", "Tues", "Wednes", "Thurs", "Fri", "Satur"
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};
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static int leaps_to_year(int year)
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{
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return year / 4 - year / 100 + year / 400;
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}
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/* This only works for the Gregorian calendar after Jan 1 1971. */
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/* Zeller's rule */
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static int rtc_calc_weekday(struct rtc_time *tm)
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{
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int leaps_to_date;
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int day;
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if (tm->year < 1971)
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return -1;
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day = 4; /* Jan 1 1970 was a Thursday. */
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/* Number of leap corrections to apply up to end of last year */
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leaps_to_date = leaps_to_year(tm->year - 1) - leaps_to_year(1970);
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/* In Zeller's rule, January and February are treated as if they
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are months 13 and 14 of the previous year (March is still month 3) */
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const int zyear = ((tm->mon < 3) ? tm->year - 1 : tm->year);
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const int q = tm->mday;
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const int m = (tm->mon < 3) ? tm->mon + 12 : tm->mon;
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const int K = zyear % 100;
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const int J = zyear / 100;
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/*
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* This year is a leap year if it is divisible by 4 except when it is
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* divisible by 100 unless it is divisible by 400
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*
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* e.g. 1904 was a leap year, 1900 was not, 1996 is, and 2000 is.
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* Because of the way the modulo operator works with negative numbers,
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* the traditional formulation of Zeller's rule must be modified
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* slightly to make the numerator positive (i.e., add 5J instead of
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* subtracting 2J). Also subtract 1 so that Sunday is day 0.
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*/
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if ((tm->year % 4) &&
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((tm->year % 100 != 0) || (tm->year % 400 == 0)) &&
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(tm->mon > 2)) {
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/* We are past Feb. 29 in a leap year */
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day++;
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}
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day += (tm->year - 1970) * 365 + leaps_to_date +
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month_offset[tm->mon-1] + tm->mday;
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tm->wday = day % 7;
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const int h = (q + (13 * (m + 1)) / 5
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+ K + (K / 4) + (J / 4) + (5 * J) - 1) % 7;
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tm->wday = h;
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return 0;
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}
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@ -147,7 +131,7 @@ unsigned long rtc_mktime(const struct rtc_time *tm)
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void rtc_display(const struct rtc_time *tm)
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{
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printk(BIOS_INFO, "Date: %4d-%02d-%02d (%sday) Time: %2d:%02d:%02d\n",
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printk(BIOS_INFO, "Date: %5d-%02d-%02d (%sday) Time: %2d:%02d:%02d\n",
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tm->year, tm->mon, tm->mday,
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(tm->wday < 0 || tm->wday > 6) ? "unknown " : weekdays[tm->wday],
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tm->hour, tm->min, tm->sec);
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