From c2537175ecf06d1834e8ce5f5b08816269ad3393 Mon Sep 17 00:00:00 2001 From: Vadim Bendebury Date: Mon, 19 May 2014 15:43:47 -0700 Subject: [PATCH] libpaylod: fix lpgcc logic statement The -z "${V}" sure must have meant to be -n "${V}", but come to think of it, this check is not necessary, as the following check will succeed if and only if V is set to 1. BUG=none TEST=verified that adding V=1 to the environment causes the lpgcc debug statements to show up in the output. Original-Change-Id: I1eb43ef49aeb4f16aef4fbee3a1037e853f9b40f Original-Signed-off-by: Vadim Bendebury Original-Reviewed-on: https://chromium-review.googlesource.com/200501 Original-Reviewed-by: Julius Werner Original-Reviewed-by: Marc Jones (cherry picked from commit 7d69a292b1dc90e68e539e329f019098f8af5007) Signed-off-by: Marc Jones Change-Id: I63785fd9fc88b95d50ecced1f4f74a76ca68089c Reviewed-on: http://review.coreboot.org/7912 Reviewed-by: Edward O'Callaghan Reviewed-by: David Hendricks Reviewed-by: Alexandru Gagniuc Tested-by: build bot (Jenkins) --- payloads/libpayload/bin/lpgcc | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/payloads/libpayload/bin/lpgcc b/payloads/libpayload/bin/lpgcc index a555bcbc48..d54669a48a 100755 --- a/payloads/libpayload/bin/lpgcc +++ b/payloads/libpayload/bin/lpgcc @@ -27,7 +27,7 @@ ## SUCH DAMAGE. # GCC wrapper for libpayload -if [ -z "${V}" ] && [ "${V}" = 1 ]; then +if [ "${V}" = "1" ]; then DEBUGME=1 else DEBUGME=0